4,9t^2=2

Solution for 4,9t^2=2 equation:

4.9t^2=2

We move all terms to the left:

4.9t^2-(2)=0

a = 4.9; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·4.9·(-2)
Δ = 39.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{39.2}}{2*4.9}=\frac{0-\sqrt{39.2}}{9.8}
=-\frac{\sqrt{}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{39.2}}{2*4.9}=\frac{0+\sqrt{39.2}}{9.8}
=\frac{\sqrt{}}{9.8}
$